40x^2=810

Solution for 40x^2=810 equation:

40x^2=810

We move all terms to the left:

40x^2-(810)=0

a = 40; b = 0; c = -810;
Δ = b2-4ac
Δ = 02-4·40·(-810)
Δ = 129600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{129600}=360$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-360}{2*40}=\frac{-360}{80}
=-4+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+360}{2*40}=\frac{360}{80}
=4+1/2
$